(Solved): pls abswer 7. Acids, Bases, Buffers, and pH (35 points). Solution 2. Freezing polint depression y ...

7. Acids, Bases, Buffers, and $$\mathrm{pH}$$ (35 points). Solution 2. Freezing polint depression $$y=mx+b;m=$$ slope of cooling or freezing curve; $$b=y$$-intercept of freezing or cooling curve $$?\mathrm{T}=$$ (Final temperature) - (Initial Temperature) $$A{T}_1=K_1{m}_{\text{velute }}$$ $$K_{\text{r }}$$ of water $$=1.86^{?}\mathrm{C}/\mathrm{m}$$ $$K_{}$$ of stearic acid $$=4.5{}^{?}\mathrm{C}/\mathrm{m}$$ $$m_{\text{malve }}=$$ molality $$=$$ moles of solute/kg of solvent molar mass of solute $$=g$$ of solute $$/\mathrm{mol}$$ of solute 3. Acids, Bases, Buffers, and $$\mathrm{pH}$$ moles of acetic acid = moles of $$\mathrm{NaOH}$$ mass/volume percent ( $$\$\mathrm{m}/v)=($$ mass of vinegar in sample/volume of sample) $$\times 100$$ 4. Determination of Ksp Moles of $$\mathrm{OH}=$$ moles of $$\mathrm{HCl}\times (1$$ mole $$\mathrm{NaOH}/1$$ mole of $$\mathrm{HCl})$$ Molarity of $$\left[{\mathrm{OH}}^{?}\right]=$$moles of $${\mathrm{OH}}^{?}/$$ volume of $${\mathrm{OH}}^{?}$$ Molarity of $$\left[{\mathrm{Ca}}^{2+}\right]=\left[{\mathrm{OH}}^{?}\right]/2$$ $$\mathrm{Ksp}=\left[{\mathrm{Ca}}^{2?}\right]{\left[{\mathrm{OH}}^2\right]}^2$$ Molar solubility in water $$=x$$ solve for $$x$$ from Ksp $$=[x][2x{]}^2$$ Molar solubility in common ion $$=x$$ solve for $$x$$ from $$Ksp=\left[C{a}^{2+}\right][2x{]}^2$$ 5. Constant Pressure Calorimetry Density of water solution (or water) $$=$$ mass $$/$$ volume $$=1\mathrm{g}/\mathrm{mL}$$ Specific Heat of water $$(\mathrm{C})=1\mathrm{cal}/{\mathrm{g}}^{?}\mathrm{C}=4.18\mathrm{J}/{\mathrm{g}}^{?}\mathrm{C}$$ $$?\mathrm{T}=$$ (Final temperature) $$?$$ (Initial Temperature) Mass of solution = mass of acid $$+$$ mass of base $$q=($$ calories evolved or heat) $$;q=mC?T$$ Calories $$/$$ mole $$=$$ number of calories $$/$$ mole of acid $$q_{x\times n}=?mC?T$$ enthalpy of solution $$=?H=q_{\text{ran }}/$$ moles of salt Specific Heat of metal $$=C_{\text{metal }}=?\left(m_{\text{water }}\times C_{\text{water }}\times ?T_{\text{water }}/m_{\text{metal }}\times ?T_{\text{matal }}\right)$$