(Solved): please find angle of twist B Required information The aluminum rod BC(G=27GPa) is bonded to the bra ...

Required information The aluminum rod $BC(G=27\mathrm{GPa})$ is bonded to the brass rod $AB(G=38\mathrm{GPa})$. Each rod is solid and has a diameter of 11 $\mathrm{mm}$. If $T_C=15\mathrm{N}?\mathrm{m}$ and $T_B=50\mathrm{N}?\mathrm{m}$, determine the angle of twist at $C$. FBD and Equilib, eqns Using the FBDs shown, $\begin{array}{l}?M_X=0?T_A=35(\mathrm{N}?\mathrm{m})\\ ?M_X=0?T_{BC}=15(\mathrm{N}?\mathrm{m})\\ ?M_X=0?T_{AB}=35(\mathrm{N},\mathrm{m})\end{array}$ Constraint Regardless of the applied torques at B\&C, the angle of twist at $A$ is constrained to be 0 (fixed support) Deformation Note: For most of its length, the internal reactions for $AB$ are and for most of ots length, the internal reactions for $BC$ are Knowing that the angle of twist ${?}_A=0$, the angle of twist at $B$ can be written as ${?}_B=$ (deg)