(Solved): PLEASE ANSWER The proton-proton cycle thought to occur in the sun consists of the following sequence ...

The proton-proton cycle thought to occur in the sun consists of the following sequence of reactions: (1) ${}_1\mathrm{H}+{}_{\mathrm{i}}^{\mathrm{i}}\mathrm{H}?{}_{\mathrm{i}}^2\mathrm{H}+{}_{\mathrm{i}}^{\mathrm{i}}\mathrm{c}+\mathrm{v}$ (2) $:\mathrm{H}+{}_1^2\mathrm{H}?{}_2^4\mathrm{He}+?$ (3) ${}_2^3\mathrm{He}+{}_2^3\mathrm{He}?{}_2^4\mathrm{He}+{}_1^1\mathrm{H}+{}_1^1\mathrm{H}$ In these reactions ${}_i^0\mathrm{c}$ is a positron (mass $?0,000549\mathrm{u}$ ), vis a neutrino (mass approximatly $0\mathrm{u}$ ), and $y$ is a gamma ray photon (mass -0 u). Note that reaction (3) uses two helium nuclei, which are formed by two reactions of type (1) and two reactions of type (2). Calculate the total amount of energy generated by the proton-proton cycle. The atomic masses are ; H (1.007825 u), ${}_1$ H (2.014102u), ${}_2^3\mathrm{He}(3.016030\mathrm{u}),{}_2^4\mathrm{He}(4.002603\mathrm{u})$. Be sure to account for the fact that there are two electrons in two hydrogen atoms, whereas there is one electron in a single deuterium atom. The mass of one electron is $0.000549\mathrm{u}$. Number Units