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(Solved): PCR/Genotyping analysis Three gel pictures are shown - each.PCR product was digested was a restrict ...




PCR/Genotyping analysis
Three gel pictures are shown - each.PCR product was digested was a restriction enryme
SNP 1
Allele \(
SNP 3
Allele \( 1=\mathrm{A} \quad \) Allele \( 2=T \)
The restriction enzyme cuts the sequence when a  \( T \)  is present
PCR/Genotyping analysis Three gel pictures are shown - each.PCR product was digested was a restriction enryme SNP 1 Allele \( 1=\mathrm{A} . \quad \) Alele \( 2=\mathrm{G} \) The restriction enzyme cuts the sequence when a ' \( G \) ' is present resulting in a shorter product of \( 1846 p \). The uncut sequence is \( 2526 \mathrm{p} \). SNP 2 Allele \( 1=6 \quad \) Allele \( 2=C \) The restriction enzyme cuts the sequence when a ' \( \mathrm{C} \) ' is present resulting in a shorter product of 175 bp. The uncut sequence is \( 198 \mathrm{bp} \). SNP 3 Allele \( 1=\mathrm{A} \quad \) Allele \( 2=T \) The restriction enzyme cuts the sequence when a ' \( T \) ' is present resulting in a shorter product of \( 196 \mathrm{bp} \). The uncut sequence is \( 266 \mathrm{bp} \). Assume each lane numbered \( 2,3,5,6,7 \) represents a dog with that ID number (i.e. all lanes numbered 2 are from dog sample 2). Give the genotypes for dogs \( 3,5,6 \) and 7 ( 2 is given as an example). Remember, homozygotes will shown one band, heterozygotes will show two bands. (0.5 pts for each correct genotype)


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Before we fill the table, let's look at each SNP individually in each dog: SNP 1: Dog 2: AA Dog 3: GG Dog 5: GG Dog 6: AG Dog 7: GG
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