Home / Expert Answers / Advanced Physics / part-apart-bpart-cpart-d-10-problem-5-a-car-is-driving-along-a-level-and-unbanked-circula-pa390

(Solved): part Apart Bpart Cpart D (10\%) Problem 5: \( A \) car is driving along a level and unbanked circula ...



part A
part B
part C
part D
(10\%) Problem 5: \( A \) car is driving along a level and unbanked circular track of diameter d \( 0.64 \mathrm{~km} \) at a
(10\%) Problem 5: \( A \) car is driving along a level and unbanked circular track of diameter d \( 0.64 \mathrm{~km} \) at a cometant speed of \( v=25.7 \mathrm{~m} / \mathrm{st} \). \$2hincorrect Anwer invalis Format you have given an answer that is entirecy numers. Hewever, plueting in the value of \( x=15 \) into \( 3 / x \) such as \( 1 / 45 \) in not a simbelic answer. cifote and \( u \) ay en this question D A \( 25 \% \) Part (a) Write an expression for the magnitude of the acceleration of the car in terms of the given parameters. \[ a= \] Hinte: 25 s detuction per hist Hints reatining 1 Feedback: 106 dedaction per feedback: a \( 25 \% \) Part (b) What is the magritude, is meters per squared socond, of the acceleration of the car? A 25\%. Part (c) Write in expression for the minimum coefficient of friction between the car's tires and the road that is required in order to keep the car going in a circle in terms of the given parameters. a 25\% Part (d) What is the value of the minimum coefficient of friction between the car's tires and the road that is required in order to keep the can going in n circle?


We have an Answer from Expert

View Expert Answer

Expert Answer


given: diameter, d = 0.64 k m speed, v = 25.7 m/s Therefore, radius, r=d2=0.642=0.32km=32
We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe