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(Solved): 1:57 5 64 knewton.com Thus, \lim_(x->\infty )(-4x-19)/(3...

1:57 5? 64 knewton.com Thus,

\lim_(x->\infty )(-4x-19)/(3x^(2)-4x 6)=0

. Content attribution Question Evaluate the following limit using L'Hospital's rule.

\lim_(x->\infty )(-3x^(2) 19x-1)/(4x^(2)-6x 5)

Enter an exact answer. Provide your answer below:

\lim_(x->\infty )(-3x^(2) 19x-1)/(4x^(2)-6x 5)=

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(Solved): (b) \lim_(x->-\infty )(17x^(5)-3x^(8))/(13x^(8)+4x^(7)) ...

(b) \lim_(x->-\infty )(17x^(5)-3x^(8))/(13x^(8)+4x^(7))

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