(Solved): OThe mean \( \bar{x} \) and standard deviation \( s \) measure center and spread but are not a comp ...

OThe mean \( \bar{x} \) and standard deviation \( s \) measure center and spread but are not a complete description of a distribution. Data sets with different shapes can have the same mean and standard deviation. To demonstrate this fact, find \( \bar{x} \) and \( s \) for these two small data sets. Then make a stemplot of each and comment on the shape of each distribution. Click on a link fo download the data. CSV Excel JMP Mac-Text Minitab PC-fext R SPSS TI Crunchlt! Both datasets have \( \bar{x}=2.03 \) and \( s=7.5 \). The stemplots show yery different distributions. Data A is strongly left-skewed with a couple possible low outliers. Data B is equally distributed between 5 and 9 but has one high outlier at \( 12.5 \) Both datasets have \( \bar{x}=7.5 \) and \( s=2.03 \). The stemplots show very different distributions. Data A is strongly right-skewed. Data \( \mathrm{B} \) is is strongly left-skewed. Both datasets have \( \bar{x}=7.5 \) and \( s=2.03 \). The stemplots show similar distributions. Data \( \mathrm{A} \) and Data \( \mathrm{B} \) are both skewed. Both datasets have \( \bar{x}=7.5 \) and \( s=2.03 \). The stemplots show very different distributions. Data A is strongly left-skewed and Data \( B \) is equally distributed between 5 and 9 but has one high outlier at \( 12.5 \). \begin{tabular}{|l|l|} \hline\( A \) & \( B \) \\ \hline \( 9.14 \) & \( 6.58 \) \\ \hline \( 8.14 \) & \( 5.76 \) \\ \hline \( 8.74 \) & \( 7.71 \) \\ \hline \( 8.77 \) & \( 8.84 \) \\ \hline \( 9.26 \) & \( 8.47 \) \\ \hline \( 8.10 \) & \( 7.04 \) \\ \hline \( 6.13 \) & \( 5.25 \) \\ \hline \( 3.10 \) & \( 5.56 \) \\ \hline \( 9.13 \) & \( 7.91 \) \\ \hline \( 7.26 \) & \( 6.89 \) \\ \hline \( 4.74 \) & \( 12.50 \) \\ \hline \end{tabular}