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(Solved): need help please and explain. In radical chlorination of alkanes, non-equivalent hydrogens react wit ...



need help please and explain.
In radical chlorination of alkanes, non-equivalent hydrogens react with chlorine atoms at different rates. At \( 35^{\circ} \
In radical chlorination of alkanes, non-equivalent hydrogens react with chlorine atoms at different rates. At \( 35^{\circ} \mathrm{C} \), primary, secondary, and tertiary \( \mathrm{C}-\mathrm{H} \) bonds react at relative rates of \( 1: 3.9: 5.2 \) respectively. These are conditions of kinetic control where product ratios are determined by relative rates of formation. For example, if \( \mathrm{A} \) is formed twice as fast as \( \mathrm{B} \), the \( \mathrm{A} \) : \( \mathrm{B} \) product ratio will be 2 . Consider chlorination of the alkane below at \( 35^{\circ} \mathrm{C} \). 1. Specify the most reactive \( \mathrm{C}-\mathrm{H} \) bond(s), a-c. Two non-equivalent \( \mathrm{C}-\mathrm{H} \) bonds of comparable reactivity should be separated by commas, l.e. a, c. 2. Specify the site of chlorination in the major monochloro substitution product, a-c. Two products that form in comparable quantities should be separated by commas, l.e. a,c


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1. Site B, is most reactive since
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