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(Solved):   Use a double integral to find the area of the region defined as one loop of the rose \( r= ...



Use a double integral to find the area of the region defined as one loop of the rose \( r=3 \cos (3 \theta) \).
a) \( \pi \)

 

Use a double integral to find the area of the region defined as one loop of the rose \( r=3 \cos (3 \theta) \). a) \( \pi \) b) \( \frac{\pi}{6} \) c) \( \frac{\pi}{4} \) d) \( \frac{3 \pi}{4} \)


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We have to find the area of region defined as one loop of the rose by using double integral: r=3cos?(3?) Finding point of intersections, r=03cos?(3?)=
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