(Solved):   (Try cis- and trans- 1,3-dibromocyclohexane and cis- and trans- 1,4-dibromocyclohexane on ...

 

(Try cis- and trans- 1,3-dibromocyclohexane and cis- and trans- 1,4-dibromocyclohexane on your own time; see how they differ) c) 1,4-dibromo-2-methylcyclohexane; the two bromines cis- to each other and trans-to the methyl group (use a chair to show 3-D, again clearly showing relevant equatorial and axial substituents).