(Solved):   only ...two-lane highway [(two 12 ft (3.6 m) lanes) has a posted speed limit of 50 mph (8 ...

 
only ...two-lane highway [(two 12 ft (3.6 m) lanes) has a posted speed limit of 50 mph (80 kmph), and on one section has vertical curves Horizontal curve parameters are as follows: PC 16+00, PT- 32.75, A 80%, e 8.0% M-18 Sag Vertical Curve parameters are as follows: PVC 14+00, PVT 18-60, PV1-16-40 G1 -20% 24% A recent daylight crush (driver traveling eastbound and striking a stationary roadway object resulted in a fatality and Arg that 50 mph posted speed limit is an unsafe speed for the curves in question and way a major cause for crash G LALA hontal curve

The design speed of a highway is 80 kmph. There is a horizontal curve of radius 200 m on a certain locality. Safe limit of transverse coefficient of friction is 0.15. Calculate the superelevation required to maintain 75% of design speed @ a 0.18 7:04 PM ob 0.15 OC None ENG wo-lane highway [(two 12 ft (3.6 m) lanes] has a posted speed limit of 50 mph (80 kmph), and on one section, has bot tical curves. rizontal curve parameters are as follows: PC= 16+00; PT= 32+75, A-80°, e- 8.0%, M.- 18 ft Vertical Curve parameters are as follows: PVC= 14+00, PVT 18+80, PVI-16+40, G1 -2.0%, G2=+4.0% ging ecent daylight crush (driver traveling eastbound and striking a stationary roadway object) resulted in a fatality and a twout at 50 mph posted speed limit is an unsafe speed for the curves in question and was a major cause for crash Calculate rizontal curve. for a. None O b. L=1675 ft R = 1193,63 ft, f, 0.060 C_L=1675 ft R, = 1199,63 ft, f;= 0.08 L-1650 ft R = 1192.70 ft.4,-0.08