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(Solved):         On your answer sheet write the formula of the organic product or ...



On your answer sheet write the formula of the organic product or products that you would expect from the reactants in questio

 

Write the equation for the reaction by which 2-bromobutane can be prepared from butene-1.

Write the formula of each of the f

 

 

From which of the following compounds, a or b, can the hydrogen in the \( \mathrm{OH} \) radical be more easily removed?
(a)

 

On your answer sheet write the formula of the organic product or products that you would expect from the reactants in questions 1 and 2. 1. (a) (b) \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{Na} \rightarrow \) (c) \( \mathrm{CH}_{2}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{CH}=\mathrm{CH}+\mathrm{HBr} \longrightarrow \) [3] 2. (a) \( \mathrm{CH}_{3} \mathrm{CHOHCH} 3+\mathrm{KMnO}_{4}-\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \) (b) \( \mathrm{CH}_{2} \mathrm{CH}_{2} \) Write the equation for the reaction by which 2-bromobutane can be prepared from butene-1. Write the formula of each of the following compounds after the letter preceding the compound: (a) 2-chloropropane (b) 1,1-dibromopropane (c) 1,1,2,2-tetrachloroethane (d) benzyl chloride 5. Which of the following reactants, (a), (b) or (c), would you expect to react most readily? Explain your answer. (a) \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Cl}+\mathrm{HOH} \rightarrow \) (b) \( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}+\mathrm{HOH} \rightarrow \) (c) \( \mathrm{CH}_{2}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{CHCl}+\mathrm{HOH} \) From which of the following compounds, a or b, can the hydrogen in the \( \mathrm{OH} \) radical be more easily removed? (a) \( \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \) (b) Explain your answer. \( [1] \) 10. Which of the following compounds, a or \( \mathrm{b} \), is more reactive? (a) \( \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{Br} \) (b) \( \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CHBr}_{2} \) [1]


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