(Solved):     For the 3 bit parallel A/D converter shown below. The encoder input is \( C[6: 0] ...

 

 

For the 3 bit parallel A/D converter shown below. The encoder input is \( C[6: 0] \), and output is \( \mathrm{D}[2: 0] \). The truth table of the \( 8 \times 3 \) encoder is given below, find the logic representation of the encoder output. (Note: The valid inputs satisfies the equation \( \mathrm{A}[6: 0]=\mathrm{C}[6: 0] \) by design) Encoder Truth Table: 1) The logic expression of \( D 2 \) is given by: \( C n \) 2) The logic expression for \( D 1 \) is given by: \( (\mathrm{Cx} \& ! \mathrm{Cy}) \mid \mathrm{Cz} \) 3) The logic expression for D0 is given by: \( (\mathrm{Cn} \& ! \mathrm{Cm})|(\mathrm{Cu} \& ! \mathrm{Cv})|(\mathrm{Cx} \& ! \mathrm{Cy}) \mid \mathrm{Cz} \) (Note: \( \mathrm{n}, \mathrm{m}, \mathrm{u}, \mathrm{v}, \mathrm{x}, \mathrm{y}, \mathrm{z} \) are numerical indices, \& is AND, | is OR, \( ! \) is NOT) (Hint: copy the proposed answer and figure out the index number) Blank \# 1 Blank \# 2 Blank \# 3 \( \sqrt{4} \) \( \sqrt{4} \) A