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(Solved):   it is circular with radius 24mm. work out angular stress using thick curved beam theory. f ...



\( N=15 \mathrm{kN} \)

 

it is circular with radius 24mm.
work out angular stress using thick curved beam theory.

formulas needed are the following:

\( \begin{aligned} A &=\pi b^{2} \\ A_{m} &=2 \pi\left(R-\sqrt{R^{2}-b^{2}}\right) \\ A &=\pi b h \\ A_{m} &=\frac{2 \pi b}{h

 

 
full working out please.

\( N=15 \mathrm{kN} \) \( \begin{aligned} A &=\pi b^{2} \\ A_{m} &=2 \pi\left(R-\sqrt{R^{2}-b^{2}}\right) \\ A &=\pi b h \\ A_{m} &=\frac{2 \pi b}{h}\left(R-\sqrt{R^{2}-h^{2}}\right) \\ A &=\pi\left(b_{1}^{2}-b_{2}^{2}\right) \\ A_{m} &=2 \pi\left(\sqrt{R^{2}-b_{2}^{2}}-\sqrt{R^{2}-b_{1}^{2}}\right) \\ A &=\pi\left(b_{1} h_{1}-b_{2} h_{2}\right) \\ A_{m} &=2 \pi\left(\frac{b_{1} R}{h_{1}}-\frac{b_{2} R}{h_{2}}-\frac{b_{1}}{h_{1}} \sqrt{R^{2}-h_{1}^{2}}+\frac{b_{2}}{h_{2}} \sqrt{R^{2}-h_{2}^{2}}\right) \end{aligned} \)


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