(Solved):
Based on the inverting op amp in Figure 3 : Figure 3: An inverting op amp for Question 3. ...
Based on the inverting op amp in Figure 3 : Figure 3: An inverting op amp for Question 3. (a) Prove that the response \( v_{\text {out }}=-\frac{R_{f}}{R_{1}} v_{\text {in }} \) by applying the KVL technique. (b) Draw the network configuration for the non-inverting amplifier and calculate the output for the case of \( V_{\mathrm{in}}=5 \sin 3 t \mathrm{mV}, R_{1}=4.7 \mathrm{k} \Omega \), and \( R_{f}=47 \mathrm{k} \Omega \).