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(Solved):   A 4.272-g sample of a mixture containing only \( \mathrm{Cu}_{2} \mathrm{O} \) and \( \mat ...



A 4.272-g sample of a mixture containing only \( \mathrm{Cu}_{2} \mathrm{O} \) and \( \mathrm{CuO} \) was treated with hydrog

 

A 4.272-g sample of a mixture containing only \( \mathrm{Cu}_{2} \mathrm{O} \) and \( \mathrm{CuO} \) was treated with hydrogen to produce \( 3.690 \mathrm{~g} \) of pure copper metal. Calculate the percentage composition (by mass) of the mixture. Percent of \( \mathrm{Cu}_{2} \mathrm{O}= \) Percent of \( \mathrm{CuO}= \) 3 item attempts remaining


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Solution: Mass of Cu2O and CuO mixture = 4.272g Mass of Cu = 3.690g The reaction of mixture with hydrogen is, Cu2O + H2
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