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(Solved):   3)Open-Circuit and Short-Circuit Test results of a 20 KVA, \( 2400 / 240 \mathrm{~V}, 60 \ ...



3)Open-Circuit and Short-Circuit Test results of a 20 KVA, \( 2400 / 240 \mathrm{~V}, 60 \mathrm{~Hz} \) transformer are give

 

3)Open-Circuit and Short-Circuit Test results of a 20 KVA, \( 2400 / 240 \mathrm{~V}, 60 \mathrm{~Hz} \) transformer are given below: Open-Circuit Test: \[ \text { Voc }=240 \mathrm{~V} \quad l o c=0.214 \mathrm{~A} \quad P o c=30 \mathrm{~W} \] Short-Circuit Test: \[ \text { Vsc }=240 \mathrm{~V} \quad \text { Isc }=8.33 \mathrm{~A} \quad \text { Psc }=600 \mathrm{~W} \] (a)Draw the equivalent circuit with all impedances at the High Voltage side. (b)Draw the equivalent circuit with all impedances at the Low Voltage side. (c)Draw the equivalent circuit with all impedances in Per-Unit. (d)The transformer supplies half-rated power to the load connected at the secondary terrminals. The load voltage is the rated voltage. The power factor of the load is \( 0.92 \) lagging.By using the equivalent circuit where all impedances are at the High Voltage side(part (a) above) calculate: (i)supply voltage and input current (ii)voltage regulation of the transformer (iii)efficiency of the transformer (.33 points)


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