2. The figure shows a simple combustion process, the mechanical details of which we can ignore. Let us consider only the combustion of methane for the calculation of: a) The input Kmoles of methane (16 Kg input), material A, oxygen and nitrogen b) The Kmoles of carbon dioxide, water, nitrogen and oxygen CH. 100% F-16.0 kg Burner A-300 kg Aire 0, N? Mol % 21.0 79.0 100.0 P= ? (kg mol) CO? N?2 0? H?0 - ? *Reaction: CH4 + 2 02 -> CO2 + 2H2O That is: 1 Kmol of CH4 reacts with 2 Kmol of 02 to give as a product 1 Kmol of CO2 and 2 Kmol of H20.

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2. The figure shows a simple combustion process, the
mechanical details of which we can ignore. Let us
consider only the comb

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