(Solved):   1011 Student Number (Name) : Passive Sign Convention Current Division \[ \mathrm{V}_{\math ...

 

1011 Student Number (Name) : Passive Sign Convention Current Division \[ \mathrm{V}_{\mathrm{R}}=9 \mathrm{~V}, \mathrm{I}_{\mathrm{R}}=3 \mathrm{~A} \] Q1. Find \( P_{\text {total }} \) \[ v=i_{1} R_{1}=i_{2} R_{2}=\frac{\square}{R_{1}+R_{2}} i_{s} . \] Q2. Is it resistor or voltage source? \[ i_{1}=\frac{\square}{R_{1}+R_{2}} i_{s}, \] \[ i_{2}=\frac{\square}{R_{1}+R_{2}} i_{s} . \] Load Resistor Circuit Q3. Is it power delievered to circuit or extracted from the circuit element? Q4. Please fill in the box \[ \mathrm{R}_{\mathrm{eq}}=\frac{(\mathrm{l})}{(\mathrm{I})} \] Using current Division, (Assume \( \mathrm{I}_{1} \) is the tota current) Voltage Division \[ \mathrm{I}_{\mathrm{L}}= \] (b) \[ v_{1}=i R_{1}=v_{s} \frac{\square}{R_{1}+R_{2}} \text {, } \] \[ P_{L}= \] \[ v_{2}=i R_{2}=v_{s} \frac{\square}{R_{1}+R_{2}} \]