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(Solved): n Acetic acid reacts with NaOH. At equilibrium the [CH3COOH]=0.470 and the [CH3COO]=0.225 K ...



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Acetic acid reacts with \( \mathrm{NaOH} \). At equilibrium the \( \left[\mathrm{CH}_{3} \mathrm{COOH}\right]=0.470 \) and th
Acetic acid reacts with . At equilibrium the and the What is the of this solution? Hint: You have been given all the variables in the Ka expression except for . Solve for and then calculate


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