(Solved): Moving electric charges experience a force when they pass through a magnetic field. For an isolate ...

Moving electric charges experience a force when they pass through a magnetic field. For an isolated charge \( q \), the force is given by \( \mathbf{F}=q(\mathbf{v} \times \mathbf{B}) \) where - \( \mathbf{B} \) is the magnetic field, and - \( \mathbf{v} \) is the velocity of the isolated charge. Suppose that a proton with an electric charge of \( 1.2 \times 10^{-19} \mathrm{C} \) is moving in a magnetic field of magnitude \( 3.24 \mathrm{~T} \) and reaches point \( P \) at a velocity of \( 397 \mathrm{~m} / \mathrm{s} \). Upon knowing that the magnitude of the magnetic force is \( 8.33 \times 10^{-17} \mathrm{~N} \), What is the angle between the path at the point \( P \) and the magnetic field? Angle: