(Solved): Monochromatic light is incident on (and perpendicular to) two slits separated by 0.235 mm, which c ...

Monochromatic light is incident on (and perpendicular to) two slits separated by 0.235 mm, which causes an interference pattern on a screen 674 cm away. The light has a wavelength of 656.3 nm. (a) What is the fraction of the maximum intensity at a distance of 0.600 cm from the central maximum of the interference pattern? I = 1 I max You may have treated the argument of the squared cosine function as having units of degrees rather than radians. Be sure to set your calculator to radian mode. (b) What If? What is the minimum distance (absolute value, in mm) from the central maximum where you would find the intensity to be half the value found in part (a)? mm