magnesium reacts with hydrochloric acid according to the following equation:

$Magnesium reacts with hydrochloric acid according to the following equation. \[ \mathrm{Mg}(\mathrm{s})+2 \mathrm{HCl}(\mathr$

Magnesium reacts with hydrochloric acid according to the following equation. $Mg (s) + 2 HCl (aq) ? MgCl_{2} (aq) + H_{2} (g)$ Suppose $0.745 g$ of $Mg$ reacts with $1.56 mL$ of $0.845 M HCl$ . What is the limiting reactant? $Mg$ $H_{2}$ $MgCl_{2}$ $HCl$ Determine the number of moles of $H_{2}$ produced in this reaction.

Question

magnesium reacts with hydrochloric acid according to the following equation:

$Magnesium reacts with hydrochloric acid according to the following equation. \[ \mathrm{Mg}(\mathrm{s})+2 \mathrm{HCl}(\mathr$

Magnesium reacts with hydrochloric acid according to the following equation.

Mg (s) + 2 HCl (aq) ? MgCl_{2} (aq) + H_{2} (g)

Suppose

0.745 g

of

Mg

reacts with

1.56 mL

of

0.845 M HCl

. What is the limiting reactant?

Mg

H_{2}

MgCl_{2}

HCl

Determine the number of moles of

H_{2}

produced in this reaction.

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