(Solved): Lead (IV) oxide dissolves in concentrated hydrochloric acid according to the ...

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Lead (IV) oxide dissolves in concentrated hydrochloric acid according to the following equation: $${\mathrm{PbO}}_2(\mathrm{s})+4\mathrm{HCl}(\mathrm{aq})?{\mathrm{PbCl}}_2(\mathrm{s})+{\mathrm{Cl}}_2(\mathrm{g})+2{\mathrm{H}}_2\mathrm{O}(\mathrm{l})$$ Starting with $$37.2\mathrm{g}$$ of lead (IV) oxide, calculate: a) the volume of 12 moldm $${}^{?3}\mathrm{HCl}$$ needed to completely dissolve it b) the mass of $${\mathrm{PbCl}}_2$$ produced c) the volume of chlorine produced at $$298\mathrm{K}$$ and $$100\mathrm{kPa}$$.