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(Solved): KE=CKE =1910128Cool Down!!Extra 73: A small block of mass m slides along a frictionless loop-the-loo ...



KE=CKE =1910128Cool Down!!Extra 73: A small block of mass m slides along a frictionless loop-the-loop. At what height h above the bottom of the loop should the block be released so that the normal force exerted on it by the track at the top of the loop is equal to the block's weight?FRICTIONLESS/Ruir



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