Home / Expert Answers / Mechanical Engineering / just-need-the-last-part-answered-2-points-torsion-lever-02-dimensions-problem-statement-lever-pa433

(Solved): Just need the last part answered (2 points) torsion lever 02 Dimensions: Problem Statement: Lever \ ...



(2 points) torsion lever 02
Dimensions:
Problem Statement:
Lever \( A B \) has a rectangular cross-section, and is composed oThe maximum force \( F \) that may be applied to the lever while maintaining a factor of safety of 3 against yielding lever \Just need the last part answered

(2 points) torsion lever 02 Dimensions: Problem Statement: Lever \( A B \) has a rectangular cross-section, and is composed of a material with a yielding strength of \( 42 \mathrm{ksi} \), and an elastic modulus of \( 25 \mathrm{Mpsi} \). It is securely welded to shaft \( \mathrm{BC} \), which has the circular cross-section shown in the figure. Shaft BC is composed of a material that has a yielding strength in shear of \( 25 \mathrm{ksi} \), and a modulus of rigidity of \( 4.9 \mathrm{Mpsi} \). The dimensions indicated on the figure are given in the table above. Find the following: Answers: The polar second moment of area of shaft \( \mathrm{BC} \) is: \[ J_{B C}= \] The maximum force \( F \) that may be applied to the lever while maintaining a factor of safety of 3 against yielding shaft \( \mathrm{BC} \) is: \( F_{\text {max allowed by shaft }}= \) The second moment of area of lever \( \mathrm{AB} \) about its neutral axis is: \[ I_{A B}= \] The maximum force \( F \) that may be applied to the lever while maintaining a factor of safety of 3 against yielding lever \( \mathrm{AB} \) is: \( F_{\text {max allowed by lever }}= \) The maximum force \( F \) that may be applied to the lever while maintaining a factor of safety of 3 against yielding lever \( A B \) is: \( F_{\text {max allowed by lever }}= \) Note: treat the whole lever as if it has a solid rectangular cross-section. Neglect the difference in \( I_{A B} \) that might arise at \( B \) due to the hole. If lever \( \mathrm{AB} \) was constrained from rotating at \( \mathrm{B} \), then the deflection of point \( \mathrm{A} \) while carrying the overall maximum permissible applied force \( F \) would be: \( \delta_{\text {beam deflection only }}= \) While carrying the overall maximum permissible applied force \( F \), the angle of twist of shaft BC is: \[ \theta_{B C}= \] Accounting for the deformation of both lever AB and shaft BC, the deflection of point A while carrying the overall maximum permissible applied force \( F \) is: \[ \delta_{\text {overall }}= \] Note: use the assumption that the deflections are "small." be sure to include units with your answers


We have an Answer from Expert

View Expert Answer

Expert Answer


refe
We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe