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(Solved): In the figure here, a ball is thrown up onto a roof, landing 3.80 s later at height h=19.0m above ...




In the figure here, a ball is thrown up onto a roof, landing \( 3.80 \) s later at height \( h=19.0 \mathrm{~m} \) above the
In the figure here, a ball is thrown up onto a roof, landing s later at height above the release level. The ball's path just before landing is angled at with the roof. (a) Find the horizontal distance dit travels. (Hint: One way is to reverse the motion, as if it is on a video.) What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's initial velocity? (a) Number Unit (b) Number Unit (c) Number Unit


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a) Apply kinematic equation ,yf=yi+vosin??t+12a2vo=(12gt2)?yisin?65t=(0.5×9.8×3.82)?19sin?65×3.8=15.02ms
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