(Solved): In an engineering design office, a shaft is being designed. Calculate the position of the centre of ...

In an engineering design office, a shaft is being designed. Calculate the position of the centre of gravity of the solid shaft formed when the plane figure bounded by the curve , ?the -axis and the ordinates = 2 ?and = 6 ?rotates about the x-axis. SEE PICTURE ATTACHED. ive asked previous and think i was given the wrong answer. they had 10+8ln (2) ?i need a numerical figure. with this answer it equals around 15.5 ?where i think the answer should be between 4 ?and 6 In an engineering design office, a shaft is being designed. Calculate the position of the centre of gravity \bar{x} of the solid shaft formed when the plane figure bounded by the curve y=f(x)=(1)/(10-x^(')), the x-axis and the ordinates x=2 and x=6 rotates about the x -axis. \bar{x} =(\int_(x=a)^b xy^(2)dx)/(\int_(x=a)^b y^(2)dx) and ()/(bar) (y)=0