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(Solved): (i) (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. \( ...



(i)
(a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas.
\( \begin{array}{cr}\mathrm{W

(i) (a) For the paths IAF, IBF, and IF in the figure above, calculate the work done on the gas. \( \begin{array}{cr}\mathrm{W}_{I A F}= & \mathrm{J} \\ \mathrm{W}_{I B F}= & \mathrm{J} \\ \mathrm{W}_{I F}= & \mathrm{J}\end{array} \) (b) For the paths IAF,IBF, and IF in the figure above, calculate the net energy transferred to the gas by heat in the process. \( \begin{aligned} \mathrm{Q}_{I A F}= & \mathrm{J} \\ \mathrm{Q}_{I B F}= & \mathrm{J} \\ \mathrm{Q}_{I F}=[ & \mathrm{J}\end{aligned} \)


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According to the question, given that: Let P1 = 1.50atm => 1.5×1.013×10?Pa = 1.52×10?Pa. P2 = 2atm => 2×1.013×10?Pa = 2.026×10?Pa. V1 = 0.300L. => 0.3
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