(Solved): How do I find the Lifting Condensation Level? Questions 4-10. 1-3 was done in class Determine the Re ...

Determine the Relative Humidity, Dew Point, and Lifting Condensation Level: 1. The temperature is $30^{?}\mathrm{F}$ and it contains $3.5\mathrm{g}/\mathrm{kg}$ of water vapor. $RH:100\%DP=30^{?}LCL=0$ $\frac{35}{35}=1\times 100=100$ 2. The temperature is $50^{?}\mathrm{F}$ and it contains $5.70\mathrm{g}/\mathrm{kg}$ of water vapor. BH: $81\%D=40^{?}LCL=2.2$ 3. The temperature is $70^{?}\mathrm{F}$ and it contains $3.5\mathrm{g}/\mathrm{kg}$ of water vapor. $50?\frac{3.5}{1}=\mathrm{san}$ RH: $22\%$ Dew point: $30^{?}\mathrm{LCl}=8.8$ $\frac{35}{15.9}=\frac{0.22}{\frac{5.6}{22.3}}$ $\frac{40}{4?5}?8$ 4. The temperature is $80^{?}\mathrm{F}$ and it contains $5.60\mathrm{g}/\mathrm{kg}$ of water vapor. $\mathrm{RH}:25\%\text{ DP }:41^{?}$ 5. The temperature is $80^{?}\mathrm{F}$ and it contains $11.56\mathrm{g}/\mathrm{kg}$ of water vapor. $RH=51\%DP.60^{?}$ $\frac{11.56}{22.3}=51.8$ 6. The temperature is $30^{?}\mathrm{F}$ and the mixing ratio is 3.5 $\mathrm{hH}:100\%\text{ Ph: }30^{?}$ $\frac{3.5}{3.5}=1$ 7. The temperature is $70^{?}\mathrm{F}$ and the mixing ratio is 8.32 . $\text{ RH:53\% DP: }52\text{ ? }$ 8. The temperature is $70^{?}\mathrm{F}$ and the mixing ratio is 3.66 . $\mathrm{RH}:23\%\text{ P: }30^{?}$ $\frac{8.32}{15.6}=.53$ $\frac{3.66}{15.6}?23$ 9. The temperature is $80^{?}\mathrm{F}$ and the mixing ratio is 17.59 . RH: $78\%$ DP: $72.5^{?}$ $\frac{17.59}{22?3}=.78$ 10. The temperature is $50^{?}\mathrm{F}$ and the mixing ratio is 6.54 . $RH:86\%DP:46^{?}\frac{6.54}{7.6}=.86$