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(Solved): How do I find the force equivalent to the load q1 and the point load F1 acting on the beam?   ...



How do I find the force equivalent to the load q1 and the point load F1 acting on the beam?

- \( l_{1}=3 \mathrm{~m}, l_{2}=3 \mathrm{~m}, l_{3}=4 \mathrm{~m} \), and \( l_{4}=0.2 \mathrm{~m} \).
- \( F_{1}=42 \mathrm

 

- \( l_{1}=3 \mathrm{~m}, l_{2}=3 \mathrm{~m}, l_{3}=4 \mathrm{~m} \), and \( l_{4}=0.2 \mathrm{~m} \). - \( F_{1}=42 \mathrm{kN}, \theta=35^{\circ} \) and \( q_{1}=6 \mathrm{kN} / \mathrm{m} \) Answer the following questions: - Determine the force equivalent to the distributed load \( q_{1} \) and the point load \( F_{1} \) acting on the beam. - Specify its location on the beam, measured from A. Put your result in the cell bellow.


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sum of vertical forces = FY FY=q1×[l1+l2]+12×l3×q+F1sin?[?]FY=6×6+
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