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(Solved): how did he put the number of cycles like that (I need explination about the cycles) Page 4 of 10 les ...



how did he put the number of cycles like that (I need explination about the cycles)

Page 4 of 10
lestion 3: Performance of a MIPS program
(15 pts) The following code fragment processes two single-precision flo
The above code is executed on a processor with a \( 2 \mathrm{GHz} \) clock that requires the following number of cycles for
Page 4 of 10 lestion 3: Performance of a MIPS program (15 pts) The following code fragment processes two single-precision floating-point arrays and , and modifies the array . Each array consists of 500 single-precision floats. The addresses of and are stored in and respectively. Note that there is an outer loop and an inner loop in the MIPS assembly language code. The above code is executed on a processor with a clock that requires the following number of cycles for each instruction:


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Solution:a)Total_Instructions= 4 (outside outer loop) + 7 (outer loop)*500 + 7 (inner loop)* 500*500=1,753,504b) Clock_Cycles= 4
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