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(Solved): he shear strength of each of ten test spot welds is determined, yielding the following data (psi). ...



he shear strength of each of ten test spot welds is determined, yielding the following data (psi).
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he shear strength of each of ten test spot welds is determined, yielding the following data (psi). \( \begin{array}{llllllllll}368 & 372 & 362 & 358 & 375 & 409 & 389 & 367 & 378 & 415\end{array} \) decimal places.) average \( \quad \) psi standard deviation \( \quad \) psi (Round vour answer to two decimal places.) psi decimal places.)


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Answer: Given data, 368,372,362,358,375,409,389,367,378,415 a) Mean ?=?Xn Mean =368+372+362+
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