(Solved): Given the circuit shown in Fig. 10, determine the frequency for which the impedance across the capa ...
Given the circuit shown in Fig. 10, determine the frequency for which the impedance across the capacitor C1 should have the same magnitude as the value of the resistor R1. What should the peak-to-peak voltage magnitude across the capacitor be when R1 and C1 have the same impedance and the function generator outputs 8Vp?p? ? Record this voltage magnitude in the calculated column in Table 4 (over the page). Show all working. Figure 10: RC Circuit
Given the circuit shown in Fig. 7, calculate the frequency for which the impedance across the inductor L1 has the same magnitude as the value of the resistor R1. Note that XFG1 is a function generator and XSC1 is an oscilloscope. What should the peak-to-peak voltage magnitude across the inductor be when R1 and L1 have the same impedance and the function generator outputs 10Vp?p? ? (Hint: Use voltage divider rule with vectors for impedances. Note that the answer is not 5Vp?p? !) Record the calculated inductor voltage in Table 3 (two pages ahead). Figure 7: RL Circuit
In an RC circuitThe impedance of the capacitor is given by where ? is the angular frequency and C is the capacitance. The magnitude of the impedance is For the impedance across the capacitor C1 to have the same magnitude as the value of the resistor R1, we need to have:|Zc| = R1 1/(?C) = R1 ? = 1/(R1*C)Substituting the values for R1 and C1, we get: