(Solved): \[ \frac{\sin (-180+\theta) \sin (-180-\theta) \sin (90+\theta) \tan (-360+\theta)}{\tan (\theta) \ ...

\[ \frac{\sin (-180+\theta) \sin (-180-\theta) \sin (90+\theta) \tan (-360+\theta)}{\tan (\theta) \sin (-270+\theta) \cos (-90-\theta) \cos (180-\theta)} \] make ongres smpre, acure and positwe use jundornentan roentives ro july simpliy to a single ratio (if hecessory)