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(Solved): For single slit diffraction we have as a condition for nodes... wsin(\theta _(n))=n\lambda Given ...



For single slit diffraction we have as a condition for nodes...

wsin(\theta _(n))=n\lambda

Given that the maximum value of the sin function is 1 , determine the highest value of

n

for light of wavelength 665 nm diffracting through a slit of width 10 microns (

=10,000nm

. ) note: There must be a max value for n because the path difference can never be greater than the width of the slit.



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