Find the definite integral
\int_2^3 8tdt
using the Fundamental Theorem of Calculus and the antiderivative
F(t)=4t^(2)
.
\int_2^3 8tdt=F(b)-F(a)
where
b= F(b)=
a=i F(a)=i
so,
\int_2^3 8tdt=