(Solved): Find out the equilibrium conversion (Xe) for the following reversible liqu ...

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Find out the equilibrium conversion $$\left(X_e\right)$$ for the following reversible liquid phase reaction (in a flow reactor) with equimolar $$A$$ and $$B$$ are in the feed to the reactor. The reaction is at $$400\mathrm{K}$$ and $$10\mathrm{atm}$$ pressure. The reaction rate follows the elementary rate law. $$A+B??2C$$ Where the equilibrium rate constant $$K_C=10\left(\mathrm{mol}/{\mathrm{dm}}^3\right)$$ with $$C_{AO}=C_{BO}=2$$ $$\mathrm{mol}/{\mathrm{dm}}^3$$. Hints: Express the concentrations $$(C_A,C_B$$ and $$C_C)$$ in terms of $$X$$ and $$C_{AO}$$ forming a stoichiometric table. ( 5 marks) At equilibrium the net rate $$\left(?r_A=0\right)$$, find the equilibrium conversion $$\left(X_e\right)$$ ? (5 marks)