(Solved): Figure 6.1: Diagrams showing the components of gravity (g= perpendicular component; gs= s ...

Figure 6.1: Diagrams showing the components of gravity $(g_{?}=$ perpendicular component; $g_s=$ slope component) on a rock sitting on flat, slightly steep, and very steep surfaces. In order for a rock (or any material) on a slope to remain stationary, frictional forces must be greater than or equal to $g_s$ (the component of gravity parallel to the slope) Figure 6.2: Microscopic views of: $(A)$ the pore space between sediment grains, and $(B)$ a pore space along a planar feature between two different rock types (for example: along a fracture or fault). The weight of water in saturated materials creates an outward acting fluid pressure in pore spaces and fractures. This so-called pore pressure becomes greater whenever the overlying column of water increases.