(Solved): equilibrium comstant For the reaction below, \( \mathrm{Kc}=7.2 \times 10^{-4} \). Note \( \mathrm{K ...

For the reaction below, \( \mathrm{Kc}=7.2 \times 10^{-4} \). Note \( \mathrm{Kc} \) is sometimes called \( \mathrm{K} \). What is the equilibrium concentration of NOF if the reaction begins with \( 0.92 \mathrm{M} \mathrm{NO} \) and \( 0.92 \mathrm{M} \mathrm{F}_{2} \) ? \[ 2 \mathrm{NO}(\mathrm{g})+\mathrm{F}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NOF}(\mathrm{g}) \]