(Solved): E. coli cells are rod-shaped, about \( 2 \mu \mathrm{m} \) long and \( 0.8 \mu \mathrm{m} \) in dia ...

E. coli cells are rod-shaped, about \( 2 \mu \mathrm{m} \) long and \( 0.8 \mu \mathrm{m} \) in diameter. E. coli has a protective cell envelope \( 10 \mathrm{~nm} \) thick. fraction of the envelope in the total volume: What percentage of the total volume of the bacterium does the cell envelope occupy? E. coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter percentage of the ribosomes in the total volume: \( 18 \mathrm{~nm} \) ), which carry out protein synthesis. What percentage of the cell volume do the ribosomes occupy? The molecular weight of an \( E \). coli DNA molecule is about \( 3.1 \times 10^{9} \mathrm{~g} / \mathrm{mol} \). The average molecular weight of a DNA length: nucleotide pair is \( 660 \mathrm{~g} / \mathrm{mol} \), and each nucleotide pair contributes \( 0.34 \mathrm{~nm} \) to the length of DNA. Calculate the length of an \( E \). coli DNA molecule. ompare the length of the DNA molecule with the length of ne bacteria. Now, consider the photomicrograph showing the How does the DNA molecule fit into the bacterial cell? ingle DNA molecule of the bacterium \( E \). coli leaking out of a lisrupted cell. The DNA must remain outside the cell. The DNA must be divided into smaller molecules. The DNA must be tightly coiled. The DNA must be packed into a nucleus. "