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(Solved): Draw the structure of Asparagine (pI=5.4) at: pH=3.0 and pH=7.6. ...

$Draw the structure of Asparagine \( (\mathrm{pI}=5.4) \) at: \( \mathrm{pH}=3.0 \) and \( \mathrm{pH}=7.6 \).$

Draw the structure of Asparagine

(pI = 5.4)

at:

pH = 3.0

and

pH = 7.6

.

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The normal structure of asparagine at pH = 5.4 is - pI = 5.4 indicated that at this pH the structure stays in its zwitter ionic form.NH2COO-NH3+O

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