Draw the sequence impedance diagram in per unit on a base 200MVA 220kV in the transmission lines. Find the equivalent positive sequence impedance as seen from the mid point of line B.

$$ G_{1} \& G_{2}: 104 \mathrm{MVA}, 11.8 \mathrm{KV}, x_{1}=x_{2}=0.2 $ p.u., $ x_{0}=0.1 $ p.u. \( T_{1} \& T_{2}: 125 \$

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Draw the sequence impedance diagram in per unit on a base 200MVA 220kV in the transmission lines. Find the equivalent positive sequence impedance as seen from the mid point of line B.

$$ G_{1} \& G_{2}: 104 \mathrm{MVA}, 11.8 \mathrm{KV}, x_{1}=x_{2}=0.2 $ p.u., $ x_{0}=0.1 $ p.u. \( T_{1} \& T_{2}: 125 \$

$ G_{1} \& G_{2}: 104 \mathrm{MVA}, 11.8 \mathrm{KV}, x_{1}=x_{2}=0.2 $ p.u., $ x_{0}=0.1 $ p.u. $ T_{1} \& T_{2}: 125 \mathrm{MVA}, 11 Y-220 \mathrm{YKV}, x_{1}=x_{2}=x_{0}=0.1 $ p.u. $ T_{3} \& T_{4}: 120 \mathrm{MVA}, 230 \mathrm{Y}-6.9 \mathrm{YKV}, x_{1}=x_{2}=x_{0}=0.12 $ p.u. $ M_{1}: 175 \mathrm{MVA}, 6.6 \mathrm{KV}, x_{1}=x_{2}=0.3 $ p.u. $ x_{0}=0.15 $ p.u. $ M_{2}: 50 \mathrm{MVA}, 6.9 \mathrm{KV}, x_{1}=x_{2}=0.3 $ p.u. $ x_{0}=0.1 $ p.u. Transmission line reactances $ : x_{1}=x_{2}=30 \Omega x_{0}=60 \Omega $

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