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(Solved): Determine the pH of a solution by constructing an ICE table, writing the equilibrium constant expr ...



Determine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and
using this infoDetermine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and
using this infoDetermine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and
using this info

Determine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. Complete Parts 1-3 before submitting your answer. 3 2 NEXT > 1 A solution is prepared with 0.0075 M HC4H7O2 and 0.085 M NaC4H7O2. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products.. HC4H7O?(aq) + H?O(1) H3O+ (aq) + C4H7O? (aq) Initial (M) Change (M) Equilibrium (M) 0 0.0075 -X 0.0075 + x 0.0075 - x 0.085-x -2x 0.085 - 2x 0.085 0.0075 + 2x 1.5 x 10-² 0.0075 - 2x +xX 0.085 + x RESET +2x 0.085 + 2x Determine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. Complete Parts 1-3 before submitting your answer. PREV 1 2 3 NEXT > < The Ka for this solution of HC4H?O is 1.5 × 10-5. Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = 1.5 × 10-5 RESET [0.0075 + x] [0] [2x] [1.5 x 10-] [0.085 + x] [0.0075 -x] [0.085 + 2x] [0.0075] [0.0075 + 2x] [0.085] [0.0075 - 2x] [x] [0.085 -x] [2x]² [0.085 - 2x] Determine the pH of a solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. Complete Parts 1-3 before submitting your answer. < PREV 1 2 3 Based on your ICE table (Part 1) and the equilibrium expression for Ka (Part 2), determine the pH of the solution.. pH = RESET 0 13.54 1.3 x 10€ 8.12 0.085 5.88 1.07 2.12 0.0075


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