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(Solved): Determine if the two functions are inverse to each other: \( f(x)=4 x-8 \) and \( g(x)=\frac{x}{4} ...



Determine if the two functions are inverse to each other:
\( f(x)=4 x-8 \) and \( g(x)=\frac{x}{4}+2 \)
Yes, they are inverseDetermine if the two functions are inverse to each other:
\( f(x)=x^{3}-8 \) and \( g(x)=\sqrt[3]{x+8} \)
Yes, they are inverDetermine the inverse of the function
\[
f(x)=\frac{2}{3+x}
\]
\[
\begin{array}{l}
f^{-1}(x)=\frac{3+x}{2} \\
f^{-1}(x)=\fracDetermine the inverse of the function
\[
f(x)=\frac{2 x-3}{4+x}
\]
\[
\begin{array}{l}
f^{-1}(x)=\frac{4 x+3}{2-x} \\
f^{-1}(Determine the inverse of the function
\[
f(x)=x^{\frac{2}{3}}-4
\]
\[
\begin{array}{l}
f^{-1}(x)=(4+x)^{\frac{3}{2}} \\
f^{-1

Determine if the two functions are inverse to each other: \( f(x)=4 x-8 \) and \( g(x)=\frac{x}{4}+2 \) Yes, they are inverse to each other No, they are NOT inverse to each other Determine if the two functions are inverse to each other: \( f(x)=x^{3}-8 \) and \( g(x)=\sqrt[3]{x+8} \) Yes, they are inverse to each other No, they are NOT inverse to each other Determine the inverse of the function \[ f(x)=\frac{2}{3+x} \] \[ \begin{array}{l} f^{-1}(x)=\frac{3+x}{2} \\ f^{-1}(x)=\frac{3+x}{2+x} \\ f^{-1}(x)=\frac{2}{x}+3 \\ f^{-1}(x)=\frac{2}{x}-3 \end{array} \] None Determine the inverse of the function \[ f(x)=\frac{2 x-3}{4+x} \] \[ \begin{array}{l} f^{-1}(x)=\frac{4 x+3}{2-x} \\ f^{-1}(x)=\frac{4 x-3}{2-x} \\ f^{-1}(x)=\frac{4 x+3}{2+x} \\ f^{-1}(x)=\frac{4 x-3}{2+x} \end{array} \] None Determine the inverse of the function \[ f(x)=x^{\frac{2}{3}}-4 \] \[ \begin{array}{l} f^{-1}(x)=(4+x)^{\frac{3}{2}} \\ f^{-1}(x)=(4-x)^{\frac{3}{2}} \\ f^{-1}(x)=4+x^{\frac{3}{2}} \\ f^{-1}(x)=(4+x)^{\frac{2}{3}} \end{array} \] None


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Two functions are inverse to each other when f(g(x))=
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