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(Solved): DESIGN OF A TWO-WAY SLAB SUPPORTED ON FOUR SIDES The general layout of a reinforced concrete office ...



student submitted image, transcription available belowDESIGN OF A TWO-WAY SLAB SUPPORTED ON FOUR SIDES The general layout of a reinforced concrete office floor is shown in the Figure. An allowance of 0.5 kPa is to be made for the partitions that are not deflection sensitive. The imposed (live load) is 3 kPa. To satisfy the fire and durability requirements, take f^(')c=32MPa and a suitable clear cover. Limit the total deflection to Delta//L_(ef)=1//250 and use Class N reinforcement Desian the reinforcement for the corner slab. Data Given: E_(c)=30100MPa,gamma_(rc)=25kN//m^(3),epsi_(cs)=600 xx10^(-6) Concrete cover =25mm For the tutorial assessment: (i) Check the slab depth based on deemed to comply requirement E prescribed in AS 3600-2018 (ii) Design for flexural reinforcement in short-span considering slab dept (can you also include references to aus standards/tables/sections etc)

DESIGN OF A TWO-WAY SLAB SUPPORTED ON FOUR SIDES The general layout of a reinforced concrete office floor is shown in the Figure. An allowance of 0.5 \\( \\mathrm{kPa} \\) is to be made for the partitions that are not deflection sensitive. The imposed (live load) is 3 \\( \\mathrm{kPa} \\). To satisfy the fire and durability requirements, take \\( \\mathrm{f}^{\\prime}{ }_{\\mathrm{c}}=32 \\mathrm{MPa} \\) and a suitable clear cover. Limit the total deflection to \\( \\Delta / L_{e f}=1 / 250 \\) and use Class \\( N \\) reinforcement. Design the reinforcement for the corner slab. Data Given: \\( E_{c}=30100 \\mathrm{MPa}, \\gamma_{\\mathrm{rc}}=25 \\mathrm{kN} / \\mathrm{m}^{3}, \\varepsilon_{\\mathrm{cs}}=600 \\times 10^{-6} \\) Concrete cover \\( =25 \\mathrm{~mm} \\) Design Workshop Assessment Tasks For the tutorial assessment: (i) Check the slab depth based on deemed to comply requirement prescribed in AS 3600-2018 (ii) Design for flexural reinforcement in short-span considering slab depth \\( D= \\) \\( 140 \\mathrm{~mm} \\) (iii) Check for Deflection: Consider: E At midspan: \\( I_{g}=232 \\times 10^{6} \\mathrm{~mm}^{4} ; M_{c r}=8.30 \\) \\( \\therefore \\mathrm{kN}-\\mathrm{m} \\mathrm{ad} \\mathrm{I}_{\\mathrm{cr}}=23.2 \\times 10^{6} \\mathrm{~mm}^{4} \\) At Interior Beam: \\( I_{g}=232 \\times 10^{6} \\mathrm{~mm}^{4} ; M_{c r}= \\) \\( 7.58 \\mathrm{kN}-\\mathrm{m} \\) ad \\( I_{c r}=24.7 \\times 10^{6} \\mathrm{~mm}^{4} \\)


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