(Solved): Data on the rate at which a volatile liquid will spread across a surface are in the table. Complete ...

Data on the rate at which a volatile liquid will spread across a surface are in the table. Complete parts a through c. $\begin{array}{cc}\text{ Time (minutes) }& \text{ Mass (Pounds) }\\ 0& 6.68\\ 2& 5.95\\ 4& 5.37\\ 6& 4.96\\ 8& 4.36\\ 10& 4.05\\ 12& 3.58\\ 14& 3.13\\ 16& 2.86\\ 18& 2.41\\ 20& 2.18\\ 25& 1.43\\ 30& 1.05\\ 45& 0.12\\ 60& 0.00\end{array}$ a. Find a $99\%$ contidence interval for the mean mass of all spills with an elapsed time of 34 minutes. Interpret the result. What is the confidence interval? (Round to three decimal places as needed.) Interpret the result. Choose the correct answer below. A. We are $99\%$ confident that the interval will contain the mean mass of the spill after 34 minutes. B. We are $99\%$ confident that the intervel will contain 34 minutes. C.We are $99\%$ confident that the interval will not contain the mean mass of the spill at 34 minutes. D.We are $99\%$ confident that the interval will contain the mean mass of the spill before 34 minutes has passed minutes. Interpret the result. What is the prediction interval? (Round to three decimal places as needed.) Interpret the result. Choose the correct answer below. A.We are $99\%$ confident that the interval will not contain the mass of the spill after 34 minutes. B.We are $99\%$ confident that the interval will contain the mass of the spill before 34 minutes has passed. C.We are $99\%$ confident that the interval will contain the mass of the spill after 34 minutes. D.We are $99\%$ confident that the interval will contain 34 minutes c. Compare the intervals, parts a and b. Which interval is wider? Will this always be the case? Explain. Fill in the blanks below.The (confidence, prediction) interval is wider. This (will not,will) always be the case because the error of this interval is random error. twice the error of the other interval. half the error of the other interval. the sum of two errors.