(Solved): Cyclic voltammetry was performed to determine the redox potential and diffusion coefficient of potas ...

Cyclic voltammetry was performed to determine the redox potential and diffusion coefficient of potassium ferricyanide. 10 runs were performed; 10 mVs, 20 mVs, 30 mVs, 40 mVs, 50 mVs, 60, mVs 70 mVs, 80 mVs, 90 mVs, and 100 mVs. The data below was retrieved.

Cyclic Voltammetry Data

µA	mV	µA	mV
1.443	198.1	-2.437	78.08
2.303	208.1	-3.354	74.07
3.018	204.1	-4.297	80.06
2.971	208.1	-4.559	59.06
2.215	194.1	-5.259	40.07
3.542	217.0	-5.368	36.04
3.952	223.1	-5.703	49.10
4.339	219.1	-6.350	55.07
4.493	226.9	-6.550	47.81
4.680	227.0	-6.855	45.05

1. Determine cathodic and anodic peak currents and voltages

2.

Cyclic Voltammetry $$5.000?\mathrm{A}$$ $$0.000\mathrm{A}$$ $$?10.00?\mathrm{A}$$ Vf (V vs. Ref.) - CURVE1 (FeCN6 100mVs-1.DTA) - CURVE2 (FeCN6 100mVs-1.DTA) - Line 1 - LIne 2 - CURVE1 (FeCN6 100mVs-1.DTA) - CURVE2 (FeCN6 100mVs-1.DTA) - CURVE1 (FeCN6 10mVs-1.DTA) CURVE2 (FeCN6 10mVs-1.DTA) - CURVE1 (FeCN6 20mVs-1.DTA) EXPERIMBNTAL PARAMETERS EXPERIMENTAL NOTES Initial E (V): 0.5 vs. Eref SPE WE-Pt, CE-C, RE-Ag/AgCl Scan Limit 1 (V): -0.25 vs. Eref $$0.1\mathrm{M}$$ KCl Scan Limit 2 (V): 0.5 vs. Eref Final E $$(\mathrm{V}\}:0.5\mathrm{vs}$$. Eref Cyclic Voltammetry $$1/26/2023$$ $$18:19:02$$ Scan Rate (mV/s): 99.9998 Step Size (mV): 1 Electrode Area $$\left({\mathrm{cm}}^{?}2\right):0.0314$$ Equil. Time $$(s):0$$ I/E Range Mode: Auto I/E Range Max current $$(\mathrm{mA}):0.00001$$ Conditioning: off Init. Delay: off IRComp: None Open Circuit (V): 0 Sampling Mode: Noise Reject \begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|} \hline $$\begin{array}{l}\text{ S c a n }\\ \mathrm{R}\text{ a t e }\\ (\mathrm{mV}/\mathrm{s})\end{array}$$ & 10 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 & 100 \\ \hline $$\begin{array}{l}{E}_{\mathrm{pc}}\\ (\mathrm{mV})\end{array}$$ & & & & & & & & & & \\ \hline $$\begin{array}{l}{E}_{\mathrm{pa}}\\ (\mathrm{mV})\end{array}$$ & & & & & & & & & & \\ \hline $$\begin{array}{l}{I}_{\mathrm{pc}}\\ (?\mathrm{A})\end{array}$$ & & & & & & & & & & \\ \hline $$\begin{array}{l}\text{ I }\\ \mathrm{pa}\\ (?\mathrm{A})\end{array}$$ & & & & & & & & & & \\ \hline \end{tabular} low with your results. 2. From the plots of the $$i_{\mathrm{p}}$$ versus scan rate $${}^{1/2,}$$ determine the slope of the best-fitting line. a. Slope of the graph $$i_{\mathrm{pc}}$$ versus scan rate $${}^{1/2}=$$ b. Slope of the graph $$i_{\mathrm{pa}}$$ versus scan rate $${}^{1/2}=$$ We use the slope from (a) for the diffusion coefficient of ferricyanide, and the slope from (b) for the the diffusion coefficient of ferrocyanide. 3. Using the Randles-Šev?ik equation and the slope from the graph of $$i_{\mathrm{pc}}$$ versus scan rate $${}^{1/2}$$, calculate the diffusion coefficient for potassium ferricyanide.