(Solved): CuCl2+NaNO3Cu(NO3)2+NaCl If 15.0g of CuCl2 reacts with 20.0g of NaNO3, how ...

$${\mathrm{CuCl}}_2+{\mathrm{NaNO}}_3?\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2+\mathrm{NaCl}$$ If $$15.0\mathrm{g}$$ of $${\mathrm{CuCl}}_2$$ reacts with $$20.0\mathrm{g}$$ of $${\mathrm{NaNO}}_3$$, how much $$\mathrm{NaCl}$$ can be formed (3 points)? What is the limiting reagent ( 2 points)? How much of the "excess" reagent is left over in this reaction (3 points)? If $$11.3\mathrm{g}$$ of $$\mathrm{NaCl}$$ are formed in the reaction, what is the percent yield of this reaction (3 points)?