(Solved): Create a plot of Ecell versus log(1/[Ag+]). Include your line of best fit and R2 on the plot. Proper ...

\begin{tabular}{|c|c|c|c|} \hline Volume of \( 0.10 \mathrm{M} \mathrm{AgNO3} \) solution added \( (\mathrm{mL}) \) & Added \( \mathrm{Ag}+ \) Volume \( (\mathrm{L}) \) & Total Volume \( (\mathrm{L}) \) & Ecell \( (\mathrm{V}) \) \\ \hline \( 2.0 \) & \( 0.0020 \) & \( 0.1020 \) & \( 0.38512 \) \\ \hline \( 4.0 \) & \( 0.0040 \) & \( 0.1040 \) & \( 0.38956 \) \\ \hline \( 6.0 \) & \( 0.0060 \) & \( 0.1060 \) & \( 0.39348 \) \\ \hline \( 8.0 \) & \( 0.0080 \) & \( 0.1080 \) & \( 0.39734 \) \\ \hline \( 10.0 \) & \( 0.0100 \) & \( 0.1100 \) & \( 0.40194 \) \\ \hline \( 12.0 \) & \( 0.0120 \) & \( 0.1120 \) & \( 0.40626 \) \\ \hline \( 14.0 \) & \( 0.0140 \) & \( 0.1140 \) & \( 0.41178 \) \\ \( 16.0 \) & \( 0.0160 \) & \( 0.1160 \) & \( 0.41651 \) \\ \hline \( 18.0 \) & \( 0.0180 \) & \( 0.1180 \) & \( 0.41902 \) \\ \hline \( 20.0 \) & \( 0.0200 \) & \( 0.1200 \) & \( 0.42440 \) \\ \hline \end{tabular}